+818 Write the equation for the perpendicular bisector of the line segment connecting the points (3,2) and (−1,7) in the form y=mx+b.
Note: The perpendicular bisector of the line segment ¯AB is the line that passes through the midpoint of ¯AB and is perpendicular to ¯AB.
+24 first find midpoint of line
(((x1+x2)/2),((y1+y2)/2))
= (((3-1)/2),((2+7)/2))
= (1,9/2)
equation of original line
1. find slope (7-2)/(-1-3) = -5/4
2. write in point slope form: y - 2= -5/4(x - 3)
3. expand into slope intercept form: y = -5/4x + 23/4
find slope of perpendicular line, which is -1/m, where m is original slope
-1/(-5/4) = 4/5
equation of perpendicular line passing through (1,9/2): y = 4/5x + 23/4
