\(\frac{\left(\frac{\left(a^nb-ab^n\right)}{2n}\right)}{3\left(a+b\right)}\)
For a and b being integers, when the result of the expression above is an integer, and n is not equal to a + b, I perdict that:
- n is prime;
- n isn't 2.
Can you prove or counter my prediction?
(a, b, n having different names implies that they have different values)