According to a study, 45% of Americans get their license before they are 18 years old. Suppose we randomly ask 20 individuals over the age of 18 if they got their license before they were 18 years old. Let X = the number of individuals who got their license before their 18th birthday.
+23254 1) I don't know what the table in your textbook looks like.
However, you can create this data by using this formula: nCr·p^r·(1-p)^r For instance, to find
0 persons: 20C0·.45^0·.55^20
1 person: 20C1·.45^1·.55^19
2 persons: 20C2·.45^2·.55^18
...
20 persons: 20C20·.45^20·.55^0
2) Exactly 11: 20C11·.45^11·.55^9
3) (assuming an exclusive between) Between 6 and 10: find the values for exactly 7, 8, and 9 and add them together.
4) At least 5 (can be done two ways, one way is): Find the values of 5, 6, 7, ..., 20 and add them togehter. (Can you find an easier way?)
5) Similar to this question in the previous problem
6) I have no idea what the graph is ...
7) Standard deviation calculation is similar to the standard deviation calculation of the previous problem.
8) Unusual -- similar to this question in the previous problem.
+23254 1) I don't know what the table in your textbook looks like.
However, you can create this data by using this formula: nCr·p^r·(1-p)^r For instance, to find
0 persons: 20C0·.45^0·.55^20
1 person: 20C1·.45^1·.55^19
2 persons: 20C2·.45^2·.55^18
...
20 persons: 20C20·.45^20·.55^0
2) Exactly 11: 20C11·.45^11·.55^9
3) (assuming an exclusive between) Between 6 and 10: find the values for exactly 7, 8, and 9 and add them together.
4) At least 5 (can be done two ways, one way is): Find the values of 5, 6, 7, ..., 20 and add them togehter. (Can you find an easier way?)
5) Similar to this question in the previous problem
6) I have no idea what the graph is ...
7) Standard deviation calculation is similar to the standard deviation calculation of the previous problem.
8) Unusual -- similar to this question in the previous problem.
