When you multiply two numbers with the same base, you add their exponents.
Logs are exponents, so the reason that they're added is to get the answer to a multiplication problem.
So, working backwards, log(4x) + log(13) = log(4x·13) = log(52x)
Since the problem says that log(52x) = 0, changing it back into eponential form: 10^0 = 52x
---> 1 = 52x
---> x = 1/52