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Suppose a\neq 0. Compute \log_{2^a} 2^b in terms of a and b.

 Dec 14, 2014

Best Answer 

 #1
avatar+23254 
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Interesting question!

Change from log notation to exponential notation:   base = 2a,   exponent = x,   answer = 2b :

 

log2a 2b = x  --->  (2a)x  =  2b   --->   2ax  =  2b   --->   ax = b   --->   x = b/a

 Dec 14, 2014
 #1
avatar+23254 
+5
Best Answer

Interesting question!

Change from log notation to exponential notation:   base = 2a,   exponent = x,   answer = 2b :

 

log2a 2b = x  --->  (2a)x  =  2b   --->   2ax  =  2b   --->   ax = b   --->   x = b/a

geno3141 Dec 14, 2014

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