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How many integers $n$ satisfy $(n-2)(n+4)<0$?

 Oct 26, 2014

Best Answer 

 #1
avatar+23254 
+5

Although you want (n - 2)(n + 4) < 0, look at  (n - 2)(n + 4)  =  0

This is a great place to start, because it give you the two values  -4  and  2.

This divides the number line into three sections: those numbers below -4, those numbers between -4 and 2, and those numbers greater than 2.

Now, let's go back to the original inequality:  (n - 2)(n + 4) < 0.

If you try any number smaller than -4, both of the sections  n - 2  and  n + 4  will be negative, so their answer won't be < 0.

If you try any number larger than -4 and smaller than 2, one of the sections will be negative and the other will be positive, so their product will be negative, so all these numbers work.

If you try any number larger than 2, both of the sections will be positive, so their answer won't be < 0.

Answer:  -4 < n < 2.

To get the final answer, find the integers between (and not including) -4 and 2.

 Oct 26, 2014
 #1
avatar+23254 
+5
Best Answer

Although you want (n - 2)(n + 4) < 0, look at  (n - 2)(n + 4)  =  0

This is a great place to start, because it give you the two values  -4  and  2.

This divides the number line into three sections: those numbers below -4, those numbers between -4 and 2, and those numbers greater than 2.

Now, let's go back to the original inequality:  (n - 2)(n + 4) < 0.

If you try any number smaller than -4, both of the sections  n - 2  and  n + 4  will be negative, so their answer won't be < 0.

If you try any number larger than -4 and smaller than 2, one of the sections will be negative and the other will be positive, so their product will be negative, so all these numbers work.

If you try any number larger than 2, both of the sections will be positive, so their answer won't be < 0.

Answer:  -4 < n < 2.

To get the final answer, find the integers between (and not including) -4 and 2.

geno3141 Oct 26, 2014

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