The area of a rectangle is 52 in². The length of the rectangle is 9 in. longer than the width. What is the width of the rectangle?.

The answer is 52 divide by 9,which equals to 5+7/9 (Inches)

Let x inch be the width.

$(x)(x+9)=52\\ x^2+9x-52=0\\ (x+13)(x-4)=0\\ x=-13(rejected)\;or\;x=4$

The width of the rectangle is 4 in.