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The displacement from equilibrium of an oscillating weight suspended by a spring is given by y(t) = 1/4cos6t where y is the displacement in feet and t is the time in seconds. Find the displacement when (a) t=0, (b) t=1/4, (c) t=1/2.

 Oct 17, 2014

Best Answer 

 #1
avatar+23254 
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Substitute the various value for t in the equation;  y(t) = (1/4)cos(6t)       cos is in radians

t = 0:     y(0) = (1/4)cos(6·0) --->  (1/4)cos(0) ---> 1 ft

t = 1/4:  y(1/4) = (1/4)cos(6·1/4) --->  (1/4)cos(1.5) ---> .0176 ft

t = 1/2:  y(1/2) = (1/2)cos(6·1/2) --->  (1/4)cos(3) --->  

 Oct 17, 2014
 #1
avatar+23254 
+5
Best Answer

Substitute the various value for t in the equation;  y(t) = (1/4)cos(6t)       cos is in radians

t = 0:     y(0) = (1/4)cos(6·0) --->  (1/4)cos(0) ---> 1 ft

t = 1/4:  y(1/4) = (1/4)cos(6·1/4) --->  (1/4)cos(1.5) ---> .0176 ft

t = 1/2:  y(1/2) = (1/2)cos(6·1/2) --->  (1/4)cos(3) --->  

geno3141 Oct 17, 2014

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