A formula for the nth term of a geometric sequence is: tn = a · rn - 1.
---> 16 = a · r22
---> 24 = a · r27
Dividing the top equation by the bottom equation (and cancelling out the a's): 16/24 = r22 / r27
---> 2/3 = r-5 ---> 3/2 = r5 ---> r = (3/2)1/5 (which is the fifth root of 3/2)
Since 16 = a · r22 ---> 16 = a · ( (3/2)1/5 )22 ---> a = 16 / ( (3/2)1/5 )22
To find the 43rd term: a · rn - 1 ---> 16 / ( (3/2)1/5 )22 · ( (3/2)1/5 )42 ---> 16 · (3/2)4
A formula for the nth term of a geometric sequence is: tn = a · rn - 1.
---> 16 = a · r22
---> 24 = a · r27
Dividing the top equation by the bottom equation (and cancelling out the a's): 16/24 = r22 / r27
---> 2/3 = r-5 ---> 3/2 = r5 ---> r = (3/2)1/5 (which is the fifth root of 3/2)
Since 16 = a · r22 ---> 16 = a · ( (3/2)1/5 )22 ---> a = 16 / ( (3/2)1/5 )22
To find the 43rd term: a · rn - 1 ---> 16 / ( (3/2)1/5 )22 · ( (3/2)1/5 )42 ---> 16 · (3/2)4