THE QUEST

Let x = 1-0.02  This is unnecessary but just for easier understanding.

$\text{Original expression}\\ =\dfrac{2x^{10}}{x}\\ =2x^9\\ \text{Now back-substitute the values.}\\ =2(1-0.02)^9\\ =2\cdot(0.98)^9\\ =2\cdot0.83374776213\\ =1.66749552426$