The formula for the nth term of an arithmetic sequence is: tn = a + (n - 1)d
---> 2/3 = a + 22d
---> 3/2 = a + 52d
Subtracting the top equation from the bottom equation: 5/6 = 30d ---> d = 1/36
Multiplying the top equation by 52: 104/3 = 52a + 1144d
Multiplying the bottom equation by -22: -33 = -22a - 1144d
Adding down: 5/3 = 30a ---> a = 1/18
To find the 35th term: value = 1/18 + (35 - 1)(1/36) <--- the answer.
The formula for the nth term of an arithmetic sequence is: tn = a + (n - 1)d
---> 2/3 = a + 22d
---> 3/2 = a + 52d
Subtracting the top equation from the bottom equation: 5/6 = 30d ---> d = 1/36
Multiplying the top equation by 52: 104/3 = 52a + 1144d
Multiplying the bottom equation by -22: -33 = -22a - 1144d
Adding down: 5/3 = 30a ---> a = 1/18
To find the 35th term: value = 1/18 + (35 - 1)(1/36) <--- the answer.