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Solve for x:
2x^2-4x+3=0
Thanks!
 Mar 20, 2014
 #1
avatar+128578 
+2
2x^2-4x+3=0

First, let's see if we can factor this....nope!!

We could either use the quadratic formula or use the solver on this site

I'll use the latter

2x^2-4x+3=0
 Mar 20, 2014
 #2
avatar+128578 
+2
So...we have only two complex roots!!

Note.........Any complex roots of a polynomial always occur in pairs!!

Hope this helps
 Mar 20, 2014
 #3
avatar+118608 
0
CPhill:

So...we have only two complex roots!!

Note.........Any complex roots of a polynomial always occur in pairs!!

Hope this helps



Hi Chris,
You can see the answer without needing a second post just by using the preview function.
 Mar 20, 2014
 #4
avatar+128578 
+2
Thanks, Melody...

I'm still learning about this site!!

I thought there was a way to do this, but I (obviously) couldn't figure out which buttons to push!!! (LOL!!!)
 Mar 20, 2014
 #5
avatar+118608 
0
Mojo:

Solve for x:
2x^2-4x+3=0
Thanks!



What all this means Mojo is that there are no solutions (no real ones anyway)

If you plotted 2x 2-4x+3=y It would lie completely above the y axis. Hence, y can never be 0.

140320 parabola.JPG
 Mar 20, 2014

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