twice the sum of number and 7 is equal to three times the difference of the number and 4
"the sum of a number and 7" is "x + 7"
So, "twice the sum of a number and 7" is 2 · (x + 7) = 2(x + 7)
"the difference of the number and 4" is "x - 4" = x - 4
The equation is: 2(x + 7) = x - 4
Multiply out: 2x + 14 = x - 4
Subtract x from both sides: x + 14 = -4
Subtract 14 from both sides: x = -18
"the sum of a number and 7" is "x + 7"
So, "twice the sum of a number and 7" is 2 · (x + 7) = 2(x + 7)
"the difference of the number and 4" is "x - 4" = x - 4
The equation is: 2(x + 7) = x - 4
Multiply out: 2x + 14 = x - 4
Subtract x from both sides: x + 14 = -4
Subtract 14 from both sides: x = -18