Volume of a Sphere

Assuming the problem means that the basketball has a radius of 4 inches when it is FILLED up, then here we go:

Sphere: $\frac{4}{3}\pi{r^3}$

Substitute and solve for volume:

$\frac{256}{3}\pi\text{ cubic inches}$

We divide:

$\frac{256/6}{3}\pi$

We evaluate:

44.6804288510548372040483

We round:

44.7 seconds