Pure acid is the be added to a 10% acid slution to obtain 81 L of a 20% acid solution.
? L of pure acid solution and ? L of 10% acid solution
Let x = amount of pure acid Percent of pure acid = 100% (1.00 as a decimal)
Then 81 - x = amount of the 10% acid solution
Formula: (Percent)·(Amount) + (Percent)·(Amount) = (Final Percent)·(Final Amount)
(100%)·(x) + (10%)·(81 - x) = (20%)·(81)
(1.00)·(x) + (0.10)·(81 - x) = (0.20)·(81)
x + 8.1 - 0.1x = 16.2
0.9x = 8.1
x = 8 liters of pure acid
81 - x = 72 liters of 10% acid solution
Let x = amount of pure acid Percent of pure acid = 100% (1.00 as a decimal)
Then 81 - x = amount of the 10% acid solution
Formula: (Percent)·(Amount) + (Percent)·(Amount) = (Final Percent)·(Final Amount)
(100%)·(x) + (10%)·(81 - x) = (20%)·(81)
(1.00)·(x) + (0.10)·(81 - x) = (0.20)·(81)
x + 8.1 - 0.1x = 16.2
0.9x = 8.1
x = 8 liters of pure acid
81 - x = 72 liters of 10% acid solution