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what is negative 5 times x plus 5

 

graphed???

 Oct 16, 2014

Best Answer 

 #1
avatar+23254 
+5

y = -5x + 5

It is a straight line that passes through the point (0,5) with a slope of -5.

y = mx + b is the slope-intercept form; for this problem, m = -5, b = 5.

Since the y-intercept is 5, start by placing a dot on the y-axis at 5.

Since the slope is -5, which is -5/1, to get another point, start at (0,5) and move to the right 1 and down 5; do this a couple more times, then draw the line.

 Oct 16, 2014
 #1
avatar+23254 
+5
Best Answer

y = -5x + 5

It is a straight line that passes through the point (0,5) with a slope of -5.

y = mx + b is the slope-intercept form; for this problem, m = -5, b = 5.

Since the y-intercept is 5, start by placing a dot on the y-axis at 5.

Since the slope is -5, which is -5/1, to get another point, start at (0,5) and move to the right 1 and down 5; do this a couple more times, then draw the line.

geno3141 Oct 16, 2014

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