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y=x+4

 Dec 12, 2014

Best Answer 

 #1
avatar+23254 
+5

Choose a point on the graph which is clearly on one side of the line or the other.

Place both the x-value and the y-value into the original inequality.

If those values make the inequality true, shade the side of the line that includes that point; if those values don't make the inequality true, shade the other side of the line.

For example:

For the inequality:  y > 2x - 7

First, draw the line y = 2x + 7 (making it a dashed line; if the original inequality were y ≥ 2x + 7, you would make a solid line).

Then choose a point that is not on the line:  I'll choose the point (1, 5). Put in these values into the original inequality:

Since  5 > 2(1) - 7   --->  5 > 2 - 7   --->   5 > -5   is true, shade that side of the line (the upper side).

If I had chosen the point (10, 1) --->  1 > 2(10) - 7   --->   1 > 10 - 3   --->   1 > -7  is false, so I would not have chosen that side (the lower side), and I would have again shaded the upper side.

Specific questions?

 Dec 12, 2014
 #1
avatar+23254 
+5
Best Answer

Choose a point on the graph which is clearly on one side of the line or the other.

Place both the x-value and the y-value into the original inequality.

If those values make the inequality true, shade the side of the line that includes that point; if those values don't make the inequality true, shade the other side of the line.

For example:

For the inequality:  y > 2x - 7

First, draw the line y = 2x + 7 (making it a dashed line; if the original inequality were y ≥ 2x + 7, you would make a solid line).

Then choose a point that is not on the line:  I'll choose the point (1, 5). Put in these values into the original inequality:

Since  5 > 2(1) - 7   --->  5 > 2 - 7   --->   5 > -5   is true, shade that side of the line (the upper side).

If I had chosen the point (10, 1) --->  1 > 2(10) - 7   --->   1 > 10 - 3   --->   1 > -7  is false, so I would not have chosen that side (the lower side), and I would have again shaded the upper side.

Specific questions?

geno3141 Dec 12, 2014

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