Which is a value of x, when 3x^2 + 4 = 40?
A) x = 2√3
B) x = 2√6
C) x = 2√11
D) x = 3√2
E) x = 6√2
Solve the given equation for 'x'
3x^2 = 36
x^2 =12
x = +- sqrt 12
x = +- sqrt(4*3)
x = +- 2 sqrt 3 if you are only looking for positive values x = 2 sqrt 3
Solve the given equation for 'x'
3x^2 = 36
x^2 =12
x = +- sqrt 12
x = +- sqrt(4*3)
x = +- 2 sqrt 3 if you are only looking for positive values x = 2 sqrt 3