Loading [MathJax]/jax/output/SVG/config.js
 
+0  
 
0
633
1
avatar

x^2+3x-2=0

 Nov 20, 2014

Best Answer 

 #1
avatar+23254 
+5

This problem has no easy factors.

You can either solve by completing the square or by the quadratic formula.

If you want to use the quadratic formula:  a = 1     b = 3     c = -2

x  =  [ -b ± √( b² - 4·a·c ) ] / ( 2·a )

   =  [ -3 ± √( 3² - 4·1·-2 ) ] / ( 2·1 )

   =  [ -3 ± √( 9 + 8 ) ] / ( 2 )

   =  [ -3 ± √17 ] / 2

 Nov 20, 2014
 #1
avatar+23254 
+5
Best Answer

This problem has no easy factors.

You can either solve by completing the square or by the quadratic formula.

If you want to use the quadratic formula:  a = 1     b = 3     c = -2

x  =  [ -b ± √( b² - 4·a·c ) ] / ( 2·a )

   =  [ -3 ± √( 3² - 4·1·-2 ) ] / ( 2·1 )

   =  [ -3 ± √( 9 + 8 ) ] / ( 2 )

   =  [ -3 ± √17 ] / 2

geno3141 Nov 20, 2014

3 Online Users