Loading [MathJax]/jax/output/SVG/config.js
 
+0  
 
+3
1
5440
2
avatar

(x+5)(x-5)

 Jul 14, 2014

Best Answer 

 #2
avatar+118703 
+8

This is a difference of 2 squares question.

(x+5)(x-5)=x2-52 = x2-25

 Jul 15, 2014
 #1
avatar+1006 
+8

FOIL method

 

FIRST

OUTER

INNER

LAST

 

(x + 5)(x - 5)

 

FIRST: (x * x) = x^2

OUTER: (x * -5) = -5x

INNER: (x * 5) = 5x

LAST: (5 * -5) = -25

 

x^2 - 5x + 5x - 25

 

The 'x's cancel each other out.

 

x^2 - 25 is your final answer.

 Jul 14, 2014
 #2
avatar+118703 
+8
Best Answer

This is a difference of 2 squares question.

(x+5)(x-5)=x2-52 = x2-25

Melody Jul 15, 2014

3 Online Users