LithianNerd

First, convert into vertex form by first foiling (x+7) and (2-x), which turns the equation into  \(4(-x^2-7x+2x+14)\) = \(4(-x^2-5x+14) = -4x^2-20x+56\). Then, use -b/2a to find the x-coordinate of the vertex \(20 \over 2*-4\)=-5/2. Then, just plug -5/2 into the equation to get the y-coordinate. The vertex in this case is the maximum of because the leading coefficient is negative for a quadratic equation.

i'm assuming you mean -7x

add the equations

-3x = 21

x = -7

plug in x

-28-8y=20

8y = -48

y = -6

55: AED and ACB are similar

56:

since the triangles are similar, AB is equal to 15 becuase ED / CB = AD / AB

Number 54:

since the axis of symmetry is a x = -2, the equation is \(y = (x-2)^2 + b\)

to find the equation, plug in x = -2 and y = 6 to find b

i^8 = 1

Use the ratio 20/12. 

\(20 \over 12 \)\(=\)

\(30 \over x\)

Cross multiply, and you'll get \(12x = 20*30\)

\(12x = 600\) 

\(x= 600/12 = 20\) 

Thus, 20 seeds would bloom.

\(204^2=41616\)

Or maybe the versus sign.

Quicksilver ALL DA WAY

7 x 7 x 41

waaaaaaaa......

You separate the star into 5 triangles and a pentagon.

I just figured out how to use LaTeX! So it's:

\(\frac{\sqrt{27}}{m^{2}*\sqrt{m}}\)

sqrt(27)/sqrt(m²) = sqrt(27)/m²*sqrt(m)

basically: Square root of 27 divided by m squared times the square root of m

If Gaussian prime = b,

a=b=a=b