Zectico

How do you know for certain that the ball took half of the total time to reach it's maximum height?

No, I have not done calculus yet.

I used the web2.0calculator

Here's the answer

$$\left({\frac{\left(\left(\left(\left(\left({\mathtt{56}}{\mathtt{\,\times\,}}{\mathtt{p9r3}}\right){\mathtt{\,\times\,}}{\mathtt{pr}}\right){\mathtt{\,\times\,}}{\mathtt{x2}}\right){\mathtt{\,\times\,}}{\mathtt{y4}}\right){\mathtt{\,\times\,}}{\mathtt{y620p14qr7}}\right)}{{\mathtt{5}}}}\right)$$

Edit: Nevermind, it's not fully simplified

31.9% = 0.319, so all you have to do is solve the equation 120,493 - (120,493 * 0.319^n), where n stands for the number of years. So...

120,493 - (120,493 * 0.319^4) = 119245.26 , so $119245.26 on the 4th year

120,493 - (120,493 * 0.319^9) = 120488.88 , so $120488.88 on the 9th year

(The answers where rounded to the nearest hundreth)

5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 55 + 5 + 5 + 5 = 115

5th day   : 256 cells

10th day : 8192 cells

15th day : 262144 cells

Hmm... this is the account that I've decided to try out. My problem right now is that I can't see what questions I or other members have answerd from the profile page.

Math is so hard though

I'm not sure if I understand your question fully, but here's my answer:

9 to 4  or  $${\frac{{\mathtt{9}}}{{\mathtt{4}}}}$$