1/x^2 +1/y^2/1/x+1/y=

$${\frac{\left({\frac{{\mathtt{1}}}{{{\mathtt{x}}}^{{\mathtt{2}}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{{\mathtt{y}}}^{{\mathtt{2}}}}}\right)}{\left({\frac{{\mathtt{1}}}{{\mathtt{x}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{y}}}}\right)}}$$  = ?

$$\dfrac{ \left( \dfrac{1}{x^2} + \dfrac{1}{y^2} \right) } { \left( \dfrac{1}{x} + \dfrac{1}{y} \right) } = \dfrac{ \left( \dfrac{1}{x} + \dfrac{1}{y} \right)\left( \dfrac{1}{x} + \dfrac{1}{y} \right) -2\times\dfrac{1}{x}\times\dfrac{1}{y} } { \left( \dfrac{1}{x} + \dfrac{1}{y} \right) }\\ \\ \\ = \dfrac{ \left( \dfrac{1}{x} + \dfrac{1}{y} \right) \left( \dfrac{1}{x} + \dfrac{1}{y} \right) } { \left( \dfrac{1}{x} + \dfrac{1}{y} \right) }- \dfrac{ \dfrac{2}{xy}} { \left( \dfrac{1}{x} + \dfrac{1}{y} \right) } \\ \\ \\ = \left( \dfrac{1}{x} + \dfrac{1}{y} \right) - \dfrac{2}{xy\left( \dfrac{1}{x} + \dfrac{1}{y} \right) } \\ \\ \\ = \left( \dfrac{1}{x} + \dfrac{1}{y} \right) - \dfrac{2}{x+y}$$

[ 1/x² + 1/y² ] / [ 1/x + 1/y ]

Look at all the denominators; their common denominator is x²y².

Multiply both the numerator and the denominator of the fraction by x²y²:

Numerator:  [ 1/x² + 1/y² ] · x²y²  =  y² + x²  =  x² + y²

Denominator:  [ 1/x + 1/y ] · x²y²  =  xy² + x²y  =  xy(x + y)

Answer:  [  x² + y² ] / [ xy(x + y) ]

(You can't simplify any farther.)