It is possible that this equation was meant to be:
14x2−9+6x−3=8x+3
in which case, multiply all terms by x2 -9
14+6(x2−9)x−3=8(x2−9))x+3
Express x2 - 9 as (x+3)(x-3) and cancel as appropriate
14+6(x+3)=8(x−3)
Expand bracketed terms and collect like terms on the same side
14+18+24=8x−6x
56=2x
x=28
.
14x2−9+6x−3=8x+3⇒{x=−(√211+1)15x=(√211−1)15}⇒{x=−1.0350559364222633x=0.90172260308893}
.happy 7 is correct.
If you need to show some work: 14/x² - 9 + 6/x - 3 = 8/x + 3
Multiply each term by x² to get rid of denominators:
(x²)(14/x²) - (x²)(9) + (x²)(6/x) - (x²)(3) = (x²)(8/x) + (x²)(3)
14 - 9x² + 6x - 3x² = 8x + 3x²
14 - 12x² + 6x = 8x + 3x²
14 - 15x² - 2x = 0
-15x² - 2x + 14 = 0
15x² + 2x - 14 = 0
Using the quadratic equation: x = [ -b ± √(b² -4ac) ] / (2a)
a = 15 b = 2 c = -14
x = [ -2 ± √(2² -4·15·-14) ] / (2·15)
x = [ -2 ± √(4 + 840) ] / (30)
x = [ -2 ± √(844) ] / (30)
x = [ -2 ± √4√211 ] / 30
x = [ -2 ± 2√211 ] / 30
x = [ -1 ± √211 ] / 15
It is possible that this equation was meant to be:
14x2−9+6x−3=8x+3
in which case, multiply all terms by x2 -9
14+6(x2−9)x−3=8(x2−9))x+3
Express x2 - 9 as (x+3)(x-3) and cancel as appropriate
14+6(x+3)=8(x−3)
Expand bracketed terms and collect like terms on the same side
14+18+24=8x−6x
56=2x
x=28
.