(3-2x)(x+1)=3(2x-3)
3x+3-2x^2-2x=6x-9
-2x^2-7x+12=0
X(1,2)=-(-7)+-√(-7)^2-4*(-2)*12/2(-2)=7+-√145/-4
something is wrong here/where is the mistake?
When you had 3x + 3 - 2x² - 2x = 6x - 9
---> - 2x² + x + 3 = 6x - 9
---> - 2x² - 5x + 12 = 0
it should be -5x, not -7x ...
((3−2×x)×(x+1))=3×(2×x−3)⇒{x=32x=−4}⇒{x=1.5x=−4}
