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5*2*(7+3)+7*0*(5-11)-23-(18*0)=

 Aug 4, 2014

Best Answer 

 #1
avatar+4473 
+8

5*2*(7+3)+7*0*(5-11)-23-(18*0)

Remember: pemdas [parentheses, exponents, multiplication, division, addition, & subtraction]

We must first evaluate the parentheses -->

5*2*(10)+7*0*(-6)-23-(0)

Next, we must perform multiplication -->

10*10+7*0-23 --> 100+7*0-23 --> 100 + 0 - 23 -->

Note that we had to do multiplication first so it is not 107*0-23.

Finally, we can just add and subtract to obtain our final answer -->

100 + 0 - 23 = 100 - 23 = 77.

 Aug 4, 2014
 #1
avatar+4473 
+8
Best Answer

5*2*(7+3)+7*0*(5-11)-23-(18*0)

Remember: pemdas [parentheses, exponents, multiplication, division, addition, & subtraction]

We must first evaluate the parentheses -->

5*2*(10)+7*0*(-6)-23-(0)

Next, we must perform multiplication -->

10*10+7*0-23 --> 100+7*0-23 --> 100 + 0 - 23 -->

Note that we had to do multiplication first so it is not 107*0-23.

Finally, we can just add and subtract to obtain our final answer -->

100 + 0 - 23 = 100 - 23 = 77.

AzizHusain Aug 4, 2014
 #2
avatar+8262 
+5

Answer:77

Do you want to know how to solve it?

First, do the parentheses.

(7+3)=10

(511)=6

(18×0)=0

Now, multiply.

5×2×10=100

7×0×6=0×6=0

Now add.

100+0=100

Now, subtract.

10023=77

So, 77 is the answer.

Hope it helps!

 Aug 4, 2014

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