7. The sequence follows a “times −1” pattern: 6, −6, 6, −6, ….Write a formula for the nth term of the sequence.

If you want a sequence to alternate:  -1, 1, -1, 1, -1, ...  use the expression (-1)^n

If you want a sequence to alternate:  1, -1, 1, -1, 1, ...  either use the expression (-1)^(n + 1) or the expression (-1)^(n - 1).

So:  [(-1)^(n + 1)]·6  will result in the sequence:  6, -6, 6, ...

7. The sequence follows a “times −1” pattern: 6, −6, 6, −6, ….Write a formula for the nth term of the sequence.

$$\boxed{(-1)^n*(-6)}$$