A cubical block of metal weighs 6 pounds. How much will another cube of the same metal weigh if its sides are twice as long?

measure the sides first then times it by 2. e.g. $${\mathtt{9}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\mathtt{9}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}} = {\mathtt{24}}{\mathtt{\,\times\,}}{\mathtt{2}} = {\mathtt{48}}$$ . then, like my formula, the ansewer is $${\mathtt{48}}$$ .

It equals no1 really cares work it out yourself 69 69 69 69 GET REKD M9

Let us say that each side of the original block has length 'x'; then its volume is  x³.

If you make each side twice as long, each side will have length '2x'; then its volume is (2x)³  =  8x³.

So, the new cube will have 8 times the volume of the old cube.

If the old cube weighs 6 pounds, the new cube will weigh 6 x 8  =  48 pounds.