a rectangular garden needs a fence. the gardener has a total of 44 ft of fencing. the lengh is 10 more feet than the width. whats w [width] l [length]?
+4473 Let's set up an equation after defining some variables:
L = length & W = width
L = W + 10 (length is 10 more feet than the width)
Perimeter of a rectangle is 2L + 2W...
2(W + 10) + 2W = 44.
Distribute the 2.
2W + 20 + 2W = 44.
Combine like terms and subtract 20 from both sides.
4W = 24.
Solve for W.
W = 24/4 = 6.
So, L = W + 10 = 6 + 10 = 16.
L = 16 ft.
W = 6 ft.
Check: 2L + 2W = 44.
2(16) + 2(6) = 44.
32 + 12 = 44. Yes.
+4473 Let's set up an equation after defining some variables:
L = length & W = width
L = W + 10 (length is 10 more feet than the width)
Perimeter of a rectangle is 2L + 2W...
2(W + 10) + 2W = 44.
Distribute the 2.
2W + 20 + 2W = 44.
Combine like terms and subtract 20 from both sides.
4W = 24.
Solve for W.
W = 24/4 = 6.
So, L = W + 10 = 6 + 10 = 16.
L = 16 ft.
W = 6 ft.
Check: 2L + 2W = 44.
2(16) + 2(6) = 44.
32 + 12 = 44. Yes.
