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Find the smallest square number that is divisible by each of the numbers 4, 9 and 10 ?

 

So can anyone explain this question to me nicely in a very easy way?

 

math arithmetic
 Aug 19, 2014

Best Answer 

 #1
avatar+128661 
+10

Notice, rosala that if the number is divisible by 10, the square itself must end with a "0." And the only way that's possible is if the  number we are squaring itself ends with a zero.

Let's factor each number:

4 = 2^2

9 = 3^2

10 = 5 * 2

And notice, if I select all the different factors, I get 2, 3 and 5. And multiplying them together, we get 2*3*5 = 30.

Now square this number  ....30^2 = 900

And that's the smallest square that is divisible by 4, 9 and 10 !!!!

Why does this work?? .....Note that 900 = 25*36 = 25*9*4........so 4 and 9 will divide this, and since it ends in a "0," so will 10....!!!!!

Hope that helps!!

  

 Aug 19, 2014
 #1
avatar+128661 
+10
Best Answer

Notice, rosala that if the number is divisible by 10, the square itself must end with a "0." And the only way that's possible is if the  number we are squaring itself ends with a zero.

Let's factor each number:

4 = 2^2

9 = 3^2

10 = 5 * 2

And notice, if I select all the different factors, I get 2, 3 and 5. And multiplying them together, we get 2*3*5 = 30.

Now square this number  ....30^2 = 900

And that's the smallest square that is divisible by 4, 9 and 10 !!!!

Why does this work?? .....Note that 900 = 25*36 = 25*9*4........so 4 and 9 will divide this, and since it ends in a "0," so will 10....!!!!!

Hope that helps!!

  

CPhill Aug 19, 2014
 #2
avatar+11912 
0

thank you CPhill!that helps!points for you!

 

 Aug 19, 2014

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