Loading [MathJax]/jax/output/SVG/config.js
 
+0  
 
0
590
2
avatar

f(x) = 2ln(x-3)

 Nov 24, 2014

Best Answer 

 #2
avatar+33654 
+5

if f(x) = c (a constant) then

 

c = 2ln(x-3)

 

Divide both sides by 2

(c/2) = ln(x-3)

 

Raise both sides to the power e

ec/2 = e ln(x-3)

 

But, eln(a) = a so

ec/2 = x-3

 

Add 3 to both sides

x = 3 + ec/2 

.

 Nov 24, 2014
 #1
avatar+23254 
+5

To solve for x, you need to know the value of f(x).

 Nov 24, 2014
 #2
avatar+33654 
+5
Best Answer

if f(x) = c (a constant) then

 

c = 2ln(x-3)

 

Divide both sides by 2

(c/2) = ln(x-3)

 

Raise both sides to the power e

ec/2 = e ln(x-3)

 

But, eln(a) = a so

ec/2 = x-3

 

Add 3 to both sides

x = 3 + ec/2 

.

Alan Nov 24, 2014

0 Online Users