The graph of a function is a line that passes through the points (3, 17) and (6, 32). What is the equation of this function?
My math is very rusty, admittedly, so perhaps I shouldn't pick back up the keyboard to help, but I still will regardless. If I recall, this is going to be a point-slope formula problem, followed by a slope-intercept formula problem.
Point slope formula: y−y1=m(x−x1)
Substitute the values accordingly: Treat (3,17) as y and (6,32) as y1.
Post-substitution: 17−32=m(3−6)
From there, simplify as needed.
Step 1: 17−32=m(3−6)
Step 2: −15=m(−3)
Step 3: −15−3=m(−3)−3
Step 4: 5=m
From there, take either point and, knowing the value of y, m, and x, plug in those numbers to the slope intercept formula to find b and make sure they match.
Slope intercept formula: y=mx+b
Substitutions: 17=5(3)+b and 32=5(6)+b
Calculations 1: 17=15+b and 32=30+b
Calculations 2: (17−15)=(15−15)+b and (32−30)=(30−30)+b
Solution(s): 2=b for both equations.
The likely solution is that your answer wants to be done up in slope-intercept form, in which case you would plug in your values for m and b, which would yield a final answer of y=5x+2. Hope this helped with understanding how you reached such an answer!
WELCOME BACK GOLDENLEAF!
Your method looks fine. (I have not checked all your working)
I do this in a way that is not quite mathematically correct but it works fine.
any equation of a line question I start with
gradient = gradient
riserun=riseruny−y1x−x1=y2−y1x2−x1y−17x−3=32−176−3
and then just simply
Technically this presentation is not quite right because it would make a hole at x=3, but just ignore that.
Good to be back! Albeit only on rare occasion, since I'm not in school anymore (had to drop out due to finances). And I haven't taken a maths course (to completion) since... gosh, 2016? But I'll still be here to keep my mind sharp, and to stay learned!