decide abs(z+iz) when z=iz w=z+iz=3-i+i(3-i)=3-i+3+i^2={i^2=1}=3-i+3i-1=2+2i I don't understand why i^2=-1 please help me

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decide abs(z+iz) when z=3-i w=z+iz=3-i+i(3-i)=3-i+3+i^2={i^2=1}=3-i+3i-1=2+2i I don't understand why i^2=-1 please help me

Guest Oct 27, 2014

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Best Answer

Just like π has been defined to be 3.1415926...,

i has been defined to be √-1 and so i² is -1.

In both cases one symbol has been used to replace a more complex expression.

geno3141 Oct 27, 2014

geno3141 · Answer 1 · 2014-10-27T06:22:09

Just like π has been defined to be 3.1415926...,

i has been defined to be √-1 and so i² is -1.

In both cases one symbol has been used to replace a more complex expression.