F(n) = 5 * (3 n^2 -n+4)^3

Question

0

1896

2

F(n) = 5 * (3n^2-n+4)^3

?

Guest 3 мар. 2015 г.

mgomed · Answer 1 · 2015-03-14T06:16:13

=X69 $\begin{pmatrix} & \\ & \end{pmatrix}$

MaxWong · Answer 2 · 2016-07-13T01:38:30

$\quad5(3n^2-n+4)^3\\=135n^6-135n^5+585n^4-365n^3+780n^2-240n+320$

.