9b² + 48b + 64
There are two sets of factors for 9: 9 and 1, 3 and 3
There are many sets of factors for 64: 64 and 1, 32 and 2, 16 and 4, 8 and 8
Because both of the signs are positive both groups must contain a plus sign.
Try the easiest first: (3b + 8)(3b + 8)
Since the middle two multiply to 24b and the outside two multiplfy to 24b and they sum to 48b, we found it!
9b² + 48b + 64
There are two sets of factors for 9: 9 and 1, 3 and 3
There are many sets of factors for 64: 64 and 1, 32 and 2, 16 and 4, 8 and 8
Because both of the signs are positive both groups must contain a plus sign.
Try the easiest first: (3b + 8)(3b + 8)
Since the middle two multiply to 24b and the outside two multiplfy to 24b and they sum to 48b, we found it!