Find the hypotenuse of each isosceles right triangle when the legs are of the given measure. Given = 8"
there is no option for radical 128
Use the Pythagorean Theorem: c² = a² + b²
a and b represent the lengths of the legs; so, a = 8 and b = 8 (since the triangle is isosceles)
---> c² = 8² + b² ---> c² = 64 + 64 ---> c² = 128 ---> c = √128
√128=√4∗32=√4∗16∗2=√4√16√2=2∗4∗√2=8√2