If you look at the problem 2/3 + y/3 = 1/1, you are trying to find what plus 2/3 will give you 3/3, or 1.
We know that 2/3 + 1/3 will give you 3/3, which is 1 . So y will equal 1. But if that isn't directly obvious, it can be solved with multiple steps.
It is tempting to combine the 2 and y on the top of the fractions, because they share a common denominator, but you cannot combine unlike terms.
So first subtract 2/3 from both sides of the equation.
y/3= 1/1-2/3
Let's focus on the right side for a minute, to subtract fractions, you need the denominators to be the same. So multiply the numerator and denominator of 1/1 by 3.
This will give you 3/3 - 2/3. Subtract the numerators, and keep the denominators.
y/3=1/3 Now to get y by itself, multiply both sides by 3. 3/1 * 1/3; muliply straight across.
y=3/3 or 1
+1006 First, make all the denominators equal.
23+y3=33
That way, since all of the denominators are equal, they can all be canceled out. This makes the equation:
2+y=3
Subtract 2 to isolate 'y'.
y=1
Final answer.
If you look at the problem 2/3 + y/3 = 1/1, you are trying to find what plus 2/3 will give you 3/3, or 1.
We know that 2/3 + 1/3 will give you 3/3, which is 1 . So y will equal 1. But if that isn't directly obvious, it can be solved with multiple steps.
It is tempting to combine the 2 and y on the top of the fractions, because they share a common denominator, but you cannot combine unlike terms.
So first subtract 2/3 from both sides of the equation.
y/3= 1/1-2/3
Let's focus on the right side for a minute, to subtract fractions, you need the denominators to be the same. So multiply the numerator and denominator of 1/1 by 3.
This will give you 3/3 - 2/3. Subtract the numerators, and keep the denominators.
y/3=1/3 Now to get y by itself, multiply both sides by 3. 3/1 * 1/3; muliply straight across.
y=3/3 or 1
