From a costal lookout point A 80 m above sea level a man sights two boats B and C in the same direction the angle of depression of the two boats are 13 and 24 degrees respectively find the distances od B and C a point below A and so find the distance between the boats
+23254 From point A straight down to point X and then across to point B creates a right triangle with X the right angle.
To find XB, use tan: tan(13°) = XB / 80 ---> XB = 80·tan(13°).
To find XC, use tan: tan(24°) = XC / 80 ---> XC = 80·tan(24°).
To find the distance between the two boats, find XC = XB.
+23254 From point A straight down to point X and then across to point B creates a right triangle with X the right angle.
To find XB, use tan: tan(13°) = XB / 80 ---> XB = 80·tan(13°).
To find XC, use tan: tan(24°) = XC / 80 ---> XC = 80·tan(24°).
To find the distance between the two boats, find XC = XB.
