Loading [MathJax]/jax/output/SVG/jax.js
 
+0  
 
+1
1
1
avatar+164 

What is the equation of the reflection of the line y = 2x + 1 across the line y = 5x - 3? Give your answer in slope-intercept form.

 
 Apr 5, 2025
 #1
avatar+15075 
+1

The equation of the reflection of the line y = 2x + 1 across the line y = 5x - 3.

 

Intersection:

f1(x)=f2(x)2x+1=5x33x=4x1,2=43y1,2=113=323P1,2(113,323)

gradient

m1,2=tan [12(arctan2+arctan5)]m1,2=2.9145

Point direction equation

y=m(xxP)+yPy=2.914536(x1.¯33)+3.¯66y=2.914536x3.886053+3.666667

The equation of the reflection is

f1,2(x)=y=2.914536x0.219381

laugh !

 Apr 7, 2025
edited by asinus  Apr 7, 2025

1 Online Users

avatar