Loading [MathJax]/jax/output/SVG/config.js
 
+0  
 
+1
4
1
avatar+249 

Altitudes $\overline{AD}$ and $\overline{BE}$ of acute triangle $ABC$ intersect at point $H$. If $\angle AHB = 144^\circ$ and $\angle BAH = 20^\circ$, then what is $\angle ABH$ in degrees?

 Jan 28, 2025
 #1
avatar+35 
+1

 if $\angle BAH = 20^\circ$, then by the vertical angles theorem, $\angle HAB = 20^\circ$. Since the sum of angles in a triangle is 180 degrees, $\angle ABH = 180^\circ - 20^\circ - 144^\circ = 16^\circ$.

 Jan 28, 2025

1 Online Users