A person wants to purchase two types of items, A and B, from a shop. She has $200 to spend, and she has to purchase at least 10 items. If the price of one unit of each A and B is $10 and $30, respectively, represent this problem graphically.
Here's a graph of the "feasible" region - since both x and y must be ≥ 0, t's the "purple" area lying above (and touching) the x axis : https://www.desmos.com/calculator/bzv8urp0g6........actually, the only "solutions" are all the points in the feasible area where x and y have integer values!!!
Le x represent item A; let y represent item B.
x + y ≥ 10 10x + 30y ≤ 200
To graph x + y ≥ 10 by plotting points:
If x = 0, y = 10 ---> (0, 10) If y = 0, x = 10 ---> (10,0)
Plot the two points, (0, 10) and (10, 0); draw the line that connects them; shade above the line (because of the ≥ sign).
To graph 10x + 30y ≤ 200 by plotting points
If x = 0, y = 20/3 ---> (0, 6 2/3) If y = 0, x = 20 ---> (20,0)
Plot the two points; draw the line that connects them; shade below the line (because of the ≤ sign).
Here's a graph of the "feasible" region - since both x and y must be ≥ 0, t's the "purple" area lying above (and touching) the x axis : https://www.desmos.com/calculator/bzv8urp0g6........actually, the only "solutions" are all the points in the feasible area where x and y have integer values!!!