help plz

This would be if you set up the equation it would look like this $\frac{2x}{x+2}=\frac{x}{x-4}$ if you cross-multiply you would get $2{x}^{2}-8x={x}^{2}+2x$ once you simplify you see its ${x}^{2}-10x$ once you factor x out $x(x-10)$ so the answers would be x=0 and x=10 and if you check this both solutions work for this.

The answers are x=10 and x=0