What would (A+A^b)^b be?
(A+A^b)^b
=A(1+A^(b-1))^b
That could not be further simplified.
I do not think you can do anything with that.....it is as simplified as you can make it.
Ummmm. I thought of binomial theorem.
(A+Ab)b=Ab+Cb1A2b−1+Cb2A3b−2+Cb3A4b−3.......