Processing math: 100%
 
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deleted

 Nov 9, 2019
edited by htzhang919  Nov 16, 2019
 #1
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m mod 9 = 6

m = 9 + 6 = 15

 

n mod 9 = 0

n = 9 

 

m x n = 15 x 9 = 135

The largest integer that mn is divisible by is: 

9 x 6 = 45

 Nov 9, 2019
 #2
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deleted

 Nov 10, 2019
edited by htzhang919  Nov 16, 2019
 #3
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You certainly could! I just thought that was too obvious !!!!.

 Nov 10, 2019
 #4
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deleted

 Nov 10, 2019
edited by htzhang919  Nov 16, 2019
 #5
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Here are the divisors of 135 = (1, 3, 5, 9, 15, 27, 45, 135) >>Total = 8

I don't really know what they mean!!. Try one of the divisors from 9 and up and see what you get.

 Nov 10, 2019
 #6
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deleted

 Nov 10, 2019
edited by htzhang919  Nov 16, 2019
 #7
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Here’s a copy of the original question.

 

Given that m and n are positive integers such that m6(mod9) and n0(mod9), what is the largest integer that mn is necessarily divisible by?

 

 

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GA

 Nov 16, 2019

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