How can i find the first term of a geometric sequence when the common ratio is 3 and the fifth term is 972
A formula for the nth term of a geometric sequence is: tn = a·rn-1
where a is the first term, n is the number of the term, and r is the common ratio.
If the fifth term is 972 and the common ratio is 3 ---> t5 = 972 and r = 3:
t5 = a·35-1 ---> 972 = a·34 ---> 972 = a·81 ---> a = 972/81 = 12
A formula for the nth term of a geometric sequence is: tn = a·rn-1
where a is the first term, n is the number of the term, and r is the common ratio.
If the fifth term is 972 and the common ratio is 3 ---> t5 = 972 and r = 3:
t5 = a·35-1 ---> 972 = a·34 ---> 972 = a·81 ---> a = 972/81 = 12