How do I factor these equations?

Question

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732

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How do I factor 3c^2=5c, 10x^2+9x+2=0, 9y^2 +16 =−24y and 4m^2=25?

Guest Aug 26, 2014

+33654

+5

Best Answer

3c^2 = 5c Rewrite as 3c^2 - 5c = 0 The left-hand side factors as c*(3c - 5)

10x^2 + 9x + 2 = 0 The LHS factors as (2x + 1)*(5x + 2)

9y^2 + 16 = -24y Rewrite as 9y^2 + 24y + 16 = 0 The LHS factors as (3y + 4)^2

4m^2 = 25 Rewrite as 4m^2 - 25 = 0 The LHS is the difference between two squares, so: (2m + 5)*(2m - 5)

Alan Aug 26, 2014

Alan · Answer 1 · 2014-08-26T03:29:46

3c^2 = 5c Rewrite as 3c^2 - 5c = 0 The left-hand side factors as c*(3c - 5)

10x^2 + 9x + 2 = 0 The LHS factors as (2x + 1)*(5x + 2)

9y^2 + 16 = -24y Rewrite as 9y^2 + 24y + 16 = 0 The LHS factors as (3y + 4)^2

4m^2 = 25 Rewrite as 4m^2 - 25 = 0 The LHS is the difference between two squares, so: (2m + 5)*(2m - 5)