+118703 -------------------------------------------------------------
Now I'll look at your answer GoldenLeaf.
−(4×y)=−3×x+1
The next line that you wrote is not correct!
y=34×x−14 XXXXX You don't subtract a quarter: you divide by -4!
Like this!
−(4×y)=−3x+1−4y=−3x+1−4y−4=−3x+1−4y=−3x+1−4y=3x−14
+1006 It would be nice if you could clarify exactly what you're trying to find, but I'll give it my educated guess.
Isolate 'y' from everything else first to put it into slope-intercept form.
3×x−4×y=1
−(4×y)=−3×x+1
y=34×x−14
The slope is 3/4 and the y-intercept is -1/4
Now, just plug it in to check!
34×(5)−14=72=3.5
Since the point (5,8) does not work with the equatino, (5,8) is not a point on the line.
+4 3x-4y=1 represents the equation of a line. The solutions for this equation are all the points that lie on the line. Your questions should read something more like: "Given the Equation 3x-4y=1, is (5,8) a solution". The point (5,8) are the x and y values of the equation. Plug em in. If the value on the right side (3x-4y) matches the value on the left side (1), then the point (5,8) is a solution.
+118703 -------------------------------------------------------------
Now I'll look at your answer GoldenLeaf.
−(4×y)=−3×x+1
The next line that you wrote is not correct!
y=34×x−14 XXXXX You don't subtract a quarter: you divide by -4!
Like this!
−(4×y)=−3x+1−4y=−3x+1−4y−4=−3x+1−4y=−3x+1−4y=3x−14
