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I was wondering how to evaluate Powers of Monomials. Here's a problem to use in an example: (7×c6)3

 Sep 3, 2014

Best Answer 

 #2
avatar+130477 
+5

Use the exponential law that says (am)n = am*n......so we  have

-(7c-6)3 =  -73c-18 = -343c-18

 

 Sep 3, 2014
 #1
avatar+4473 
+5

-(7c^-6)^3

 

Evaluate the terms separately:

-(7^3)[(c^-6)^3]

 

-(343)(c^(-6*3))

 

-343c^-18

 

-343/c^18.

 Sep 3, 2014
 #2
avatar+130477 
+5
Best Answer

Use the exponential law that says (am)n = am*n......so we  have

-(7c-6)3 =  -73c-18 = -343c-18

 

CPhill Sep 3, 2014

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