how do you work out 16^(2/3)

Question

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Guest Jul 29, 2014

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Best Answer

$16^\frac{2}{3} = (2^4)^\frac{2}{3}=2^\frac{8}{3}=(2^6)^\frac{1}{3}\times(2^2)^\frac{1}{3} = 2^2\times(2^2)^\frac{1}{3}=4\times4^\frac{1}{3}$

or

${{\mathtt{16}}}^{\left({\frac{{\mathtt{2}}}{{\mathtt{3}}}}\right)} = {\mathtt{6.349\: \!604\: \!207\: \!872\: \!797\: \!4}}$

Alan Jul 29, 2014

Alan · Answer 1 · 2014-07-29T10:29:34

$16^\frac{2}{3} = (2^4)^\frac{2}{3}=2^\frac{8}{3}=(2^6)^\frac{1}{3}\times(2^2)^\frac{1}{3} = 2^2\times(2^2)^\frac{1}{3}=4\times4^\frac{1}{3}$

or

${{\mathtt{16}}}^{\left({\frac{{\mathtt{2}}}{{\mathtt{3}}}}\right)} = {\mathtt{6.349\: \!604\: \!207\: \!872\: \!797\: \!4}}$

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