Cookies inc sells peanut butter cookies for 6.50 a dozen and chocolate chip cookies for 9.00. today they sold 85 dozen more peanut butter cookies than chicoalete chip cookies. the total sales for both types were $4055.50 LET P BE THE VARIABLE FOR NUMBER OF PB COOKIES SOLDS
+23254 Let P = number of dozen peanut butter cookies sold.
Let C = number of dozens chocolate chip cookies sold.
Number equation: P = 85 + C
Value equation: 6.50P + 9.00C = 4055.50
Substituting the first equation into the second:
6.50(85 + C) + 9.00C = 4055.50
552.50 + 6.50C + 9.00C = 4055.50
552.50 + 15.50C = 4055.50
15.50C = 3503.00
C = 226
P = 85 + 226 = 311
The daily sales for any given day (S) are equal to $6.50 per dozen PB cookies sold (P) plus $9.00 per dozen CC cookies sold (C).
S = 6.50P + 9.00C
The sales of this day (S) were $4055.50, so we can write that
4055.50 = 6.50P + 9.00C
Today, Cookie Inc. sold 85 more dozens of PB cookies (P) than dozens of CC cookies, so we can write that
P = C + 85
We have two unknown variables, "P" and "C." We also have two equations with these variables, meaning that we can solve for them by plugging "C + 85" for "P" into the first equation:
4055.50 = 6.50P + 9.00C
4055.50 = 6.50(C + 85) + 9.00C
Now we solve for "C"
4055.50 = 6.50(C + 85) + 9.00C
4055.50 = 6.50C + 85 * 6.5 + 9.00C
4055.50 = 15.5C + 552.5
3503 = 15.5C
226 = C
226 Dozens of Chocolate Chip Cookies were sold.
+23254 Let P = number of dozen peanut butter cookies sold.
Let C = number of dozens chocolate chip cookies sold.
Number equation: P = 85 + C
Value equation: 6.50P + 9.00C = 4055.50
Substituting the first equation into the second:
6.50(85 + C) + 9.00C = 4055.50
552.50 + 6.50C + 9.00C = 4055.50
552.50 + 15.50C = 4055.50
15.50C = 3503.00
C = 226
P = 85 + 226 = 311
